Alkyl iodide reacts with NaCN to give alkyl cyanide and small amount of alkyl isocyanide. Formation of these two products is due to the ambident character of cyanide ion

Question

Alkyl iodide reacts with NaCN to give alkyl cyanide and small amount of alkyl isocyanide. Formation of these two products is due to the (A) Ionic character of NaCN (B) Nucleophilic character of cyanide ion (C) Ambident character of cyanide ion (D) Electrophilic character of cyanide

Tardigrade Admin · Accepted Answer

Alkyl iodide reacts with NaCN to give alkyl cyanide and small amount of alkyl isocyanide. Formation of these two products is due to the ambident character of cyanide ion <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-clbdrsdzgiosd4vz.jpg" />

Q. Alkyl iodide reacts with NaCN to give alkyl cyanide and small amount of alkyl isocyanide. Formation of these two products is due to the

Ionic character of NaCN

Nucleophilic character of cyanide ion

Ambident character of cyanide ion

Electrophilic character of cyanide

Alkyl iodide reacts with NaCN to give alkyl cyanide and small amount of alkyl isocyanide. Formation of these two products is due to the ambident character of cyanide ion