Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is

Question

Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is (A) CH 3 CH = NNHCON = CHCH 3 (B) CH 3 CH = NNHCONH 2 (C) CH 3 CH = N - underset overset|OHN - CONH 2 (D) CH 3 CH = N - CONHNH 2

Tardigrade Admin · Accepted Answer

Correct answer is (b) CH 3 CH = NNHCONH 2

Q. Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is

$C H_{3} C H = NN H CON = C H C H_{3}$

$C H_{3} C H = NN H CON H_{2}$

$C H_{3} C H = N - O H ∣ N - CON H_{2}$

$C H_{3} C H = N - CON H N H_{2}$

Correct answer is (b) $C H_{3} C H = NN H CON H_{2}$

Q. Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is

CH3​CH=NNHCON=CHCH3​

CH3​CH=NNHCONH2​

CH3​CH=N−OH∣N​−CONH2​

CH3​CH=N−CONHNH2​

Correct answer is (b) CH3​CH=NNHCONH2​

$C H_{3} C H = NN H CON = C H C H_{3}$

$C H_{3} C H = NN H CON H_{2}$

$C H_{3} C H = N - O H ∣ N - CON H_{2}$

$C H_{3} C H = N - CON H N H_{2}$

Correct answer is (b) $C H_{3} C H = NN H CON H_{2}$