According to Nernst equation, which is not correct if Q=Kc :

Question

According to Nernst equation, which is not correct if Q=Kc : (A) E text cell =0 (B) (R T/n F) ln Q=E text cell ° (C) Kc=e(n F E text cell °/R T) (D) E text cell =E text cell °

Tardigrade Admin · Accepted Answer

E text cell =E text cell °-( RT /n F ) ln Q At equilibrium, E text cell =0 text and Q =K c ∴ E textcell ≠ E textcell°

Q. According to Nernst equation, which is not correct if $Q = K_{c}$ :

$E_{cell} = 0$

$\frac{RT}{n F} ln Q = E_{cell}^{\circ}$

$K_{c} = e^{\frac{n F E _{cell}^{\circ}}{RT}}$

$E_{cell} = E_{cell}^{\circ}$

$E_{cell} = E_{cell}^{\circ} - \frac{RT}{n F} ln Q$
At equilibrium,
$E_{cell} = 0 and Q = K_{c}$
$∴ E_{cell} \neq = E_{cell}^{\circ}$

Q. According to Nernst equation, which is not correct if Q=Kc​ :

Ecell ​=0

nFRT​lnQ=Ecell ∘​

Kc​=eRTnFEcell ∘​​

Ecell ​=Ecell ∘​