According to Moseley's law of X-rays the frequency (v) of a particular characteristic X-ray and the atomic number (Z) of the element depend on each other as

Question

According to Moseley's law of X-rays the frequency (v) of a particular characteristic X-ray and the atomic number (Z) of the element depend on each other as (A)  √v=kZ2 (B)  √v=(h/Z2) (C)  v=kZ  (D)  √v=kZ

Tardigrade Admin · Accepted Answer

According to Moseley's law of X-rays √v=k(Z-b) where k= proportionality constant, b= Shielding constant. Here b=0 ∴ √v=k Z

Q. According to Moseley's law of $X$ -rays the frequency $(v)$ of a particular characteristic $X$ -ray and the atomic number $(Z)$ of the element depend on each other as

$v = k Z^{2}$

$v = \frac{h}{Z ^{2}}$

$v = k Z$

$v = k Z$

According to Moseley's law of X-rays $v = k (Z - b)$
where $k =$ proportionality constant, $b =$ Shielding constant.
Here $b = 0$
$∴ v = k Z$

Q. According to Moseley's law of X-rays the frequency (v) of a particular characteristic X-ray and the atomic number (Z) of the element depend on each other as

v​=kZ2

v​=Z2h​

v=kZ

v​=kZ

According to Moseley's law of X-rays v​=k(Z−b) where k= proportionality constant, b= Shielding constant. Here b=0 ∴v​=kZ

Q. According to Moseley's law of $X$ -rays the frequency $(v)$ of a particular characteristic $X$ -ray and the atomic number $(Z)$ of the element depend on each other as

$v = k Z^{2}$

$v = \frac{h}{Z ^{2}}$

$v = k Z$

$v = k Z$

According to Moseley's law of X-rays $v = k (Z - b)$
where $k =$ proportionality constant, $b =$ Shielding constant.
Here $b = 0$
$∴ v = k Z$