According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1 × 10-31 kg is

Question

According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1 × 10-31 kg is (A) 2.8 × 10-3 m2 s-1 (B) 3 .8 × 10-5 m2 s-1 (C) 5.8 × 10-5 m2 s-1 (D) 6 .8 × 10-6 m2 s-1

Tardigrade Admin · Accepted Answer

Given that mass of electron =9.1×10-31 kg Planckâs constant =9.63×10-34 m2 s-1 By using Δ xΔ p =(h/4π); Δ x ×Δν× m=(h/4π) where: Δ x = uncertainty in position Δ x = uncertainty in position Δ x×Δν=(h/4π× m)=(6.63×10-34/4×3.14×9.1×10-31) =5.8 ×10-5 m2 s-1

Q. According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass $9.1 \times 1 0^{- 31} k g$ is

$2.8 \times 1 0^{- 3} m^{2} s^{- 1}$

$3.8 \times 1 0^{- 5} m^{2} s^{- 1}$

$5.8 \times 1 0^{- 5} m^{2} s^{- 1}$

$6.8 \times 1 0^{- 6} m^{2} s^{- 1}$

Q. According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1×10−31kg is

2.8×10−3m2s−1

3.8×10−5m2s−1

5.8×10−5m2s−1

6.8×10−6m2s−1

Given that mass of electron =9.1×10−31kg Planck’s constant =9.63×10−34m2s−1 By using ΔxΔp=4πh​;Δx×Δν×m=4πh​ where: Δx= uncertainty in position Δx= uncertainty in position Δx×Δν=4π×mh​=4×3.14×9.1×10−316.63×10−34​ =5.8×10−5m2s−1

Q. According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass $9.1 \times 1 0^{- 31} k g$ is

$2.8 \times 1 0^{- 3} m^{2} s^{- 1}$

$3.8 \times 1 0^{- 5} m^{2} s^{- 1}$

$5.8 \times 1 0^{- 5} m^{2} s^{- 1}$

$6.8 \times 1 0^{- 6} m^{2} s^{- 1}$