According to equipartition law of energy each particle in a system of particles have thermal energy E equal to

Question

According to equipartition law of energy each particle in a system of particles have thermal energy E equal to (A) E = kBT (B) E = (1/2)kBT (C) E = 3kBT (D) E = (3/2)kBT

Tardigrade Admin · Accepted Answer

According to equipartition of energy, each particle have thermal energy E equal to, E =( f /2) KT [ f = degrees of freedom ] Here, f=3 ∴ E =(3/2) KT

Q. According to equipartition law of energy each particle in a system of particles have thermal energy $E$ equal to

$E = k_{B} T$

$E = \frac{1}{2} k_{B} T$

$E = 3 k_{B} T$

$E = \frac{3}{2} k_{B} T$

According to equipartition of energy, each particle have thermal energy $E$ equal to, $E = \frac{f}{2} K T [f =$ degrees of freedom $]$
Here, $f = 3$
$< b r / > ∴ E = \frac{3}{2} K T < b r / >$

Q. According to equipartition law of energy each particle in a system of particles have thermal energy E equal to

E=kB​T

E=21​kB​T

E=3kB​T

E=23​kB​T