A zinc rod is placed in 0.095 M solution of zinc sulphate at 298 K, the potential of the electrode at this temperature is[ EZno=-0.76 volts]

Question

A zinc rod is placed in 0.095 M solution of zinc sulphate at 298 K, the potential of the electrode at this temperature is[ EZno=-0.76 volts] (A)  -0.79 volts (B)  -0.69 volts (C)  -0.59 volts (D)  -0.49 volts

Tardigrade Admin · Accepted Answer

: Ecell=Ecello+(0.0591/n) log [Zn++] Ecell=-0.76+(0.0591/n) log (0.095) =-0.76-0.030=0.79 volts.

Q. A zinc rod is placed in 0.095 M solution of zinc sulphate at 298 K, the potential of the electrode at this temperature is[ $E_{Z n}^{o} = - 0.76$ volts]

$- 0.79$ volts

$- 0.69$ volts

$- 0.59$ volts

$- 0.49$ volts

: $E_{ce ll} = E_{ce ll}^{o} + \frac{0.0591}{n} lo g [Z n^{++}]$ $E_{ce ll} = - 0.76 + \frac{0.0591}{n} lo g (0.095)$ $= - 0.76 - 0.030 = 0.79$ volts.

Q. A zinc rod is placed in 0.095 M solution of zinc sulphate at 298 K, the potential of the electrode at this temperature is[ EZno​=−0.76 volts]

−0.79 volts

−0.69 volts

−0.59 volts

−0.49 volts