Tardigrade
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Tardigrade
Question
Chemistry
A xrightarrowHCl (CH3)3C = CHCOCH3, A is
Q.
A
H
Cl
(
C
H
3
)
3
C
=
C
H
COC
H
3
,
A is
1447
197
MHT CET
MHT CET 2004
Aldehydes Ketones and Carboxylic Acids
Report Error
A
acetone
31%
B
acetaldehyde
22%
C
propionaldehyde
42%
D
formaldehyde
6%
Solution:
Acetone
(
C
H
3
COC
H
3
)
undergoes condensation reaction in presence of HCI to produce mesityl oxide.
A
2
C
H
3
COC
H
3
H
C
I
−
H
2
O
4
−
m
e
t
h
y
l
p
e
n
t
−
3
−
e
n
−
2
−
o
n
e
or
m
es
i
t
y
l
o
x
i
d
e
(
C
H
3
)
2
−
C
=
C
H
COC
H
3