A wire placed along north south direction carries a current of 5 A from south to north. Find the magnetic field due to a 1 m piece of wire at a point 200 cm north east from the piece.

Question

A wire placed along north south direction carries a current of 5 A from south to north. Find the magnetic field due to a 1 m piece of wire at a point 200 cm north east from the piece. (A) 8.8 × 10-10 T acting vertically downward. (B) 4.4 × 10-10 T, acting vertically downward (C) 2.2 × 10-10 T, acting vertically upward (D) 1.1 × 10-10 T, acting horizontally

Tardigrade Admin · Accepted Answer

dB =(μ0/4 π) × ( Id ℓ sin θ/ r 2) =(10-7 × 5 × 10-2 × sin 45/(2)2) dB=8.8 × 10-10 T Acting vertically downward.

Q. A wire placed along north south direction carries a current of $5 A$ from south to north. Find the magnetic field due to a $1 m$ piece of wire at a point $200 c m$ north east from the piece.

$8.8 \times 1 0^{- 10} T$ acting vertically downward.

$4.4 \times 1 0^{- 10} T$ , acting vertically downward

$2.2 \times 1 0^{- 10} T$ , acting vertically upward

$1.1 \times 1 0^{- 10} T$ , acting horizontally

$d B = \frac{μ _{0}}{4 π} \times \frac{I d ℓ s i n θ}{r ^{2}}$
$= \frac{1 0 ^{- 7} \times 5 \times 1 0 ^{- 2} \times s i n 45}{( 2 ) ^{2}}$
$d B = 8.8 \times 1 0^{- 10} T$
Acting vertically downward.

Q. A wire placed along north south direction carries a current of 5A from south to north. Find the magnetic field due to a 1m piece of wire at a point 200cm north east from the piece.

8.8×10−10T acting vertically downward.

4.4×10−10T, acting vertically downward

2.2×10−10T, acting vertically upward

1.1×10−10T, acting horizontally