A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Its magnetic moment is,

Question

A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Its magnetic moment is, (A) I L2 /4 A m2 (B) 1 π L2/4 A m2 (C) 2 I L2/π A m2 (D) I L2/4π A m2

Tardigrade Admin · Accepted Answer

2π r=L r=(L/2π) M=I (A) M=I (π r2) M=I (π) ((L/2π))2 M=(IL2/4π)

Q. A wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of a circle. Its magnetic moment is,

$I L^{2} /4 A m^{2}$

$1 π L^{2} /4 A m^{2}$

$2 I L^{2} / π A m^{2}$

$I L^{2} /4 π A m^{2}$

$2 π r = L$
$r = \frac{L}{2 π}$
$M = I (A)$
$M = I (π r^{2})$
$M = I (π) (\frac{L}{2 π})^{2}$
$M = \frac{I L ^{2}}{4 π}$

Q. A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Its magnetic moment is,

IL2/4Am2

1πL2/4Am2

2IL2/πAm2

IL2/4πAm2