A wire of length 50 cm moves with a velocity of 300 m - min -1, perpendicular to a magnetic field. If the emf induced in the wire is 2 V, the magnitude of the field (in tesla) is

Question

A wire of length 50 cm moves with a velocity of 300 m - min -1, perpendicular to a magnetic field. If the emf induced in the wire is 2 V, the magnitude of the field (in tesla) is (A) 2 (B) 5 (C) 0.4 (D) 0.8

Tardigrade Admin · Accepted Answer

Emf induced in the wire is given by, ε=B l v Given, l=50 cm =0.5 m v=300 m - min -1=(300/60)=5 ms -1 e=2 V Magnetic field, B=(ε/l v)=(2/0.5 × 5)=0.80 T

Q. A wire of length $50 c m$ moves with a velocity of $300 m - min^{- 1}$ , perpendicular to a magnetic field. If the emf induced in the wire is $2 V$ , the magnitude of the field (in tesla) is

2

5

0.4

0.8

Emf induced in the wire is given by, $ε = Bl v$
Given, $l = 50 c m = 0.5 m$
$v = 300 m - min^{- 1} = \frac{300}{60} = 5 m s^{- 1}$
$e = 2 V$
Magnetic field, $B = \frac{ε}{l v} = \frac{2}{0.5 \times 5} = 0.80 T$

Q. A wire of length 50cm moves with a velocity of 300m−min−1, perpendicular to a magnetic field. If the emf induced in the wire is 2V, the magnitude of the field (in tesla) is

2

5

0.4

0.8

Emf induced in the wire is given by, ε=Blv Given, l=50cm=0.5m v=300m−min−1=60300​=5ms−1 e=2V Magnetic field, B=lvε​=0.5×52​=0.80T

Q. A wire of length $50 c m$ moves with a velocity of $300 m - min^{- 1}$ , perpendicular to a magnetic field. If the emf induced in the wire is $2 V$ , the magnitude of the field (in tesla) is

Emf induced in the wire is given by, $ε = Bl v$
Given, $l = 50 c m = 0.5 m$
$v = 300 m - min^{- 1} = \frac{300}{60} = 5 m s^{- 1}$
$e = 2 V$
Magnetic field, $B = \frac{ε}{l v} = \frac{2}{0.5 \times 5} = 0.80 T$