A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because:

Question

A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because: (A)  AgNO3 is insoluble in NaCl solution (B)  NaCl is insoluble in water (C)  NaCl is an inorganic compound (D)  Cl- ions are present in NaCl solution

Tardigrade Admin · Accepted Answer

A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because Cl- ions are present in NaCl solution.

Q. A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because:

$A g N O_{3}$ is insoluble in $N a Cl$ solution

$N a Cl$ is insoluble in water

$N a Cl$ is an inorganic compound

$C l^{-}$ ions are present in $N a Cl$ solution

A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because $C l^{-}$ ions are present in $N a Cl$ solution.

Q. A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because:

AgNO3​ is insoluble in NaCl solution

NaCl is insoluble in water

NaCl is an inorganic compound

Cl− ions are present in NaCl solution

A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because Cl− ions are present in NaCl solution.

$A g N O_{3}$ is insoluble in $N a Cl$ solution

$N a Cl$ is insoluble in water

$N a Cl$ is an inorganic compound

$C l^{-}$ ions are present in $N a Cl$ solution

A white precipitate of silver chloride is formed when sodium chloride solution is added to silver nitrate solution because $C l^{-}$ ions are present in $N a Cl$ solution.