A wheel rotates with constant acceleration of 2.0 radian / sec 2. If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately:

Question

A wheel rotates with constant acceleration of 2.0 radian / sec 2. If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately: (A) 32 (B) 24 (C) 16 (D) 8

Tardigrade Admin · Accepted Answer

θ=(α t2/2)=(2 × 100/2)=100 n=(θ/2 π)=(100/2 × 3.14) =15.92 ≈ 16

Q. A wheel rotates with constant acceleration of $2.0$ radian / $sec^{2}$ . If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately:

32

24

16

8

$θ = \frac{α t ^{2}}{2} = \frac{2 \times 100}{2} = 100$
$n = \frac{θ}{2 π} = \frac{100}{2 \times 3.14}$
$= 15.92 \approx 16$

Q. A wheel rotates with constant acceleration of 2.0 radian / sec2. If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately:

32

24

16

8

θ=2αt2​=22×100​=100 n=2πθ​=2×3.14100​ =15.92≈16

Q. A wheel rotates with constant acceleration of $2.0$ radian / $sec^{2}$ . If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately:

$θ = \frac{α t ^{2}}{2} = \frac{2 \times 100}{2} = 100$
$n = \frac{θ}{2 π} = \frac{100}{2 \times 3.14}$
$= 15.92 \approx 16$