Question

A wheel of mass $10kg$ has a moment of inertia of $160kg-m^2$ about its own axis, the radius of gyration will be

• A. 10 m
• B. 8 m
• C. 6 m
• D. 4 m

Answer 1

Answer: (D)

Here : Mass of wheel $M=10kg$
Moment of inertia $=160kg{m}^2$
(where $K$ is radius of gyration)
Using relation,
$I=M{K}^2$
$160=10\times K^2$ or $K^2=16$
or $K=4m$