A wave travelling in positive X -direction with A=0.2 m has a velocity of 360 m / sec if λ=60 m, then correct expression for the wave is

Question

A wave travelling in positive X -direction with A=0.2 m has a velocity of 360 m / sec if λ=60 m, then correct expression for the wave is (A) y=0.2 sin [2 π(6 t+(x/60))] (B) y=0.2 sin [π(6 t+(x/60))] (C) y=0.2 sin [2 π(6 t-(x/60))] (D) y=0.2 sin [π(6 t-(x/60))]

Tardigrade Admin · Accepted Answer

A wave travelling in positive x -direction may be represented as y=A sin (2 π/λ)(v t-x). On putting values y=0.2 sin (2 π/60)(360 t-x) ⇒ y=0.2 sin 2 π(6 t-(x/60))

Q. A wave travelling in positive $X$ -direction with $A = 0.2 m$ has a velocity of $360 m / sec$ if $λ = 60 m$ , then correct expression for the wave is

$y = 0.2 sin [2 π (6 t + \frac{x}{60})]$

$y = 0.2 sin [π (6 t + \frac{x}{60})]$

$y = 0.2 sin [2 π (6 t - \frac{x}{60})]$

$y = 0.2 sin [π (6 t - \frac{x}{60})]$

A wave travelling in positive $x$ -direction may be represented as $y = A sin \frac{2 π}{λ} (v t - x)$ .
On putting values $y = 0.2 sin \frac{2 π}{60} (360 t - x)$
$\Rightarrow y = 0.2 sin 2 π (6 t - \frac{x}{60})$

Q. A wave travelling in positive X -direction with A=0.2m has a velocity of 360m/sec if λ=60m, then correct expression for the wave is

y=0.2sin[2π(6t+60x​)]

y=0.2sin[π(6t+60x​)]

y=0.2sin[2π(6t−60x​)]

y=0.2sin[π(6t−60x​)]