A voltmeter has a range 0- V 1 with a series resistance R and with a series resistance 2 R, the range is 0- V 2 The correct relation between V1 and V2 is

Question

A voltmeter has a range 0- V 1 with a series resistance R and with a series resistance 2 R, the range is 0- V 2 The correct relation between V1 and V2 is (A) V2=2 V1 (B) V2>2 V (C) V2>>2 V1 (D) V2<2 V1

Tardigrade Admin · Accepted Answer

For conversion of galvanometer R is connected in series. ∴ ig=(V1/R+G) and ig=(V2/2 R+G) (V1/R+G)=(V2/2 R+G) (V2/V1)=(2 R+G/R+G) (V2/V1)=(2(R+G)-G/(R+G)) (V2/V1)=2-(G/R-G) V2=2 V1-(V1 G/(R+G)) ⇒ V2<2 V1

Q. A voltmeter has a range $0 - V_{1}$ with a series resistance $R$ and with a series resistance $2 R$ , the range is $0 - V_{2}$ The correct relation between $V_{1}$ and $V_{2}$ is

$V_{2} = 2 V_{1}$

$V_{2} > 2 V$

$V_{2} >> 2 V_{1}$

$V_{2} < 2 V_{1}$

Q. A voltmeter has a range 0−V1​ with a series resistance R and with a series resistance 2R, the range is 0−V2​ The correct relation between V1​ and V2​ is

V2​=2V1​

V2​>2V

V2​>>2V1​

V2​<2V1​

For conversion of galvanometer R is connected in series. ∴ig​=R+GV1​​ and ig​=2R+GV2​​ R+GV1​​=2R+GV2​​ V1​V2​​=R+G2R+G​ V1​V2​​=(R+G)2(R+G)−G​ V1​V2​​=2−R−GG​ V2​=2V1​−(R+G)V1​G​ ⇒V2​<2V1​

Q. A voltmeter has a range $0 - V_{1}$ with a series resistance $R$ and with a series resistance $2 R$ , the range is $0 - V_{2}$ The correct relation between $V_{1}$ and $V_{2}$ is

$V_{2} = 2 V_{1}$

$V_{2} > 2 V$

$V_{2} >> 2 V_{1}$

$V_{2} < 2 V_{1}$