A vessel is quarter filled with a liquid of refractive index μ. The remaining part of the vessel is filled with an immiscible liquid of refractive index 1.5 μ. The apparent depth of the vessel is 50 % of the actual depth. The value of μ is

Question

A vessel is quarter filled with a liquid of refractive index μ. The remaining part of the vessel is filled with an immiscible liquid of refractive index 1.5 μ. The apparent depth of the vessel is 50 % of the actual depth. The value of μ is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9babdd7edbbfa168f0fccf00800ec009-.png" /> S= text Shift =(3 h/4)(1-(2/3 μ))+(h/4)(1-(1/μ))=(h/2) Solving above equation, μ=(3/2)

Q. A vessel is quarter filled with a liquid of refractive index $μ$ . The remaining part of the vessel is filled with an immiscible liquid of refractive index $1.5 μ$ . The apparent depth of the vessel is $50%$ of the actual depth. The value of $μ$ is

$S = Shift = \frac{3 h}{4} (1 - \frac{2}{3 μ}) + \frac{h}{4} (1 - \frac{1}{μ}) = \frac{h}{2}$
Solving above equation, $μ = \frac{3}{2}$

Q. A vessel is quarter filled with a liquid of refractive index μ. The remaining part of the vessel is filled with an immiscible liquid of refractive index 1.5μ. The apparent depth of the vessel is 50% of the actual depth. The value of μ is

S= Shift =43h​(1−3μ2​)+4h​(1−μ1​)=2h​ Solving above equation, μ=23​

Q. A vessel is quarter filled with a liquid of refractive index $μ$ . The remaining part of the vessel is filled with an immiscible liquid of refractive index $1.5 μ$ . The apparent depth of the vessel is $50%$ of the actual depth. The value of $μ$ is

$S = Shift = \frac{3 h}{4} (1 - \frac{2}{3 μ}) + \frac{h}{4} (1 - \frac{1}{μ}) = \frac{h}{2}$
Solving above equation, $μ = \frac{3}{2}$