A very narrow capillary tube records a rise of 20 cm when dipped in water. When the area of cross-section is reduced to one-fourth of former value, water will rise to a height of

Question

A very narrow capillary tube records a rise of 20 cm when dipped in water. When the area of cross-section is reduced to one-fourth of former value, water will rise to a height of (A) 10 cm (B) 20 cm (C) 40 cm (D) 80 cm

Tardigrade Admin · Accepted Answer

A propto r2 ∴ radius becomes half. As Hr=constant . ∴ H becomes double.

Q. A very narrow capillary tube records a rise of $20 c m$ when dipped in water. When the area of cross-section is reduced to one-fourth of former value, water will rise to a height of

$10 c m$

$20 c m$

$40 c m$

$80 c m$

$A \propto r^{2}$
$∴$ radius becomes half.
As $Hr = co n s t an t$ .
$∴ H$ becomes double.

Q. A very narrow capillary tube records a rise of 20cm when dipped in water. When the area of cross-section is reduced to one-fourth of former value, water will rise to a height of

10cm

20cm

40cm

80cm