A vehicle of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to step the vehicle in 10 s is

Question

A vehicle of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to step the vehicle in 10 s is (A) 90 N (B) 180 N (C) 360 N (D) 720 N

Tardigrade Admin · Accepted Answer

v=108× (5/18)m text/s =30 m text/s Momentum = 120 x 30 kg-m/s (initial) Final momentum = 0 textForce=( textchange textin textmomentum/ texttime) =(120× 30/20)=180 N

Q. A vehicle of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to step the vehicle in 10 s is

90 N

180 N

360 N

720 N

$v = 108 \times \frac{5}{18} m / s$ $= 30 m / s$ Momentum = 120 x 30 kg-m/s (initial) Final momentum = 0 $Force = \frac{change in momentum}{time}$ $= \frac{120 \times 30}{20} = 180 N$

Q. A vehicle of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to step the vehicle in 10 s is

90 N

180 N

360 N

720 N

v=108×185​m/s =30m/s Momentum = 120 x 30 kg-m/s (initial) Final momentum = 0 Force=timechangeinmomentum​ =20120×30​=180N

$v = 108 \times \frac{5}{18} m / s$ $= 30 m / s$ Momentum = 120 x 30 kg-m/s (initial) Final momentum = 0 $Force = \frac{change in momentum}{time}$ $= \frac{120 \times 30}{20} = 180 N$