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Question
Physics
A uniform thermometre scale is at steady state with its 0 cm mark at 20° C and 100 cm mark at 100° C. Temperature of the 60 cm mark is
Q. A uniform thermometre scale is at steady state with its
0
c
m
mark at
2
0
∘
C
and
100
c
m
mark at
10
0
∘
C
. Temperature of the
60
c
m
mark is
3840
249
Thermal Properties of Matter
Report Error
A
4
8
∘
C
B
6
8
∘
C
C
5
2
∘
C
D
5
8
∘
C
Solution:
100
−
20
T
−
20
=
100
−
0
60
−
0
80
T
−
20
=
100
60
T
=
48
+
20
=
6
8
∘
C