A uniform thermometre scale is at steady state with its 0 cm mark at 20° C and 100 cm mark at 100° C. Temperature of the 60 cm mark is

Question

A uniform thermometre scale is at steady state with its 0 cm mark at 20° C and 100 cm mark at 100° C. Temperature of the 60 cm mark is (A) 48° C (B) 68° C (C) 52° C (D) 58° C

Tardigrade Admin · Accepted Answer

(T-20/100-20)=(60-0/100-0) (T-20/80)=(60/100) T=48+20 =68° C

Q. A uniform thermometre scale is at steady state with its $0 c m$ mark at $2 0^{\circ} C$ and $100 c m$ mark at $10 0^{\circ} C$ . Temperature of the $60 c m$ mark is

$4 8^{\circ} C$

$6 8^{\circ} C$

$5 2^{\circ} C$

$5 8^{\circ} C$

$\frac{T - 20}{100 - 20} = \frac{60 - 0}{100 - 0}$
$\frac{T - 20}{80} = \frac{60}{100}$
$T = 48 + 20$
$= 6 8^{\circ} C$

Q. A uniform thermometre scale is at steady state with its 0cm mark at 20∘C and 100cm mark at 100∘C. Temperature of the 60cm mark is

48∘C

68∘C

52∘C

58∘C