A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly, then

Question

A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly, then (A) its speed of rotation increases (B) its speed of rotation decreases (C) its speed of rotation remains same (D) its speed increases because its moment of inertia Increases

Tardigrade Admin · Accepted Answer

When a metallic rod is heated it expands. Its moment of inertia (I) about a perpendicular bisector increases. According to law of conservation of angular momentum, its angular speed (ω ) decreases, since ω × (1/l) (according to law of conservation of angular momentum).

Q. A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly, then

its speed of rotation increases

its speed of rotation decreases

its speed of rotation remains same

its speed increases because its moment of inertia Increases

When a metallic rod is heated it expands. Its moment of inertia $(I)$ about a perpendicular bisector increases. According to law of conservation of angular momentum, its angular speed $(ω)$ decreases, since $ω \times \frac{1}{l}$ (according to law of conservation of angular momentum).

Q. A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly, then

its speed of rotation increases

its speed of rotation decreases

its speed of rotation remains same

its speed increases because its moment of inertia Increases

When a metallic rod is heated it expands. Its moment of inertia (I) about a perpendicular bisector increases. According to law of conservation of angular momentum, its angular speed (ω) decreases, since ω×l1​ (according to law of conservation of angular momentum).

When a metallic rod is heated it expands. Its moment of inertia $(I)$ about a perpendicular bisector increases. According to law of conservation of angular momentum, its angular speed $(ω)$ decreases, since $ω \times \frac{1}{l}$ (according to law of conservation of angular momentum).