A triangular shaped wire carrying 10 A current is placed in a uniform magnetic field of 0.5 T, as shown in figure. The magnetic force on segment CD is (Given BC = CD = BD =5 cm ).

Question

A triangular shaped wire carrying 10 A current is placed in a uniform magnetic field of 0.5 T, as shown in figure. The magnetic force on segment CD is (Given BC = CD = BD =5 cm ). (A) 0.126 N (B) 0.312 N (C) 0.216 N (D) 0.245 N

Tardigrade Admin · Accepted Answer

F M ( CD )= BI ℓ eff =0.5 ×(10) ×(5 sin 60 × 10-2) =0.216 N

Q. A triangular shaped wire carrying $10 A$ current is placed in a uniform magnetic field of $0.5 T$ , as shown in figure. The magnetic force on segment $C D$ is
(Given $BC = C D = B D = 5 c m$ ).

$0.126 N$

$0.312 N$

$0.216 N$

$0.245 N$

$F_{M} (C D) = B I ℓ_{e ff}$
$= 0.5 \times (10) \times (5 sin 60 \times 1 0^{- 2})$
$= 0.216 N$

Q. A triangular shaped wire carrying 10A current is placed in a uniform magnetic field of 0.5T, as shown in figure. The magnetic force on segment CD is (Given BC=CD=BD=5cm ).

0.126N

0.312N

0.216N

0.245N