A transverse progressive wave on a stretched string has a velocity of 10 m/s and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be :

Question

A transverse progressive wave on a stretched string has a velocity of 10 m/s and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be : (A)  (π /2)  (B)  (3π /8)  (C)  π /4  (D)  π /8

Tardigrade Admin · Accepted Answer

upsilon =nλ 10=100λ ⇒ λ =(10/100)=(1/10)m =10cm Phase difference =(2π /λ )× path difference =(2π /10)× 2.5=(π /2)

Q. A transverse progressive wave on a stretched string has a velocity of 10 m/s and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be :

$\frac{π}{2}$

$\frac{3 π}{8}$

$π /4$

$π /8$

$υ = nλ$ $10 = 100 λ$ $\Rightarrow$ $λ = \frac{10}{100} = \frac{1}{10} m$ $= 10 c m$ Phase difference $= \frac{2 π}{λ} \times$ path difference $= \frac{2 π}{10} \times 2.5 = \frac{π}{2}$