A transformer has 500 primary turns and 10 secondary turns. If the secondary has resistive load of 15 Ω, the currents in the primary and secondary respectively, are

Question

A transformer has 500 primary turns and 10 secondary turns. If the secondary has resistive load of 15 Ω, the currents in the primary and secondary respectively, are (A) 0.16 A, 3.2 × 10-3 A (B) 3.2 × 10-3 A , 0.16 A (C) 0.16 A, 0.16 A (D) 3.2 × 10-3 A , 3.2 × 10-3 A

Tardigrade Admin · Accepted Answer

As (Ns/Np) = (Ip/Is) ⇒ (10/500) = (Ip/Is) or (Ip/Is) = (1/50) or Is = 50 Ip This condition is satisfied only when current in primary is 3.2 × 10-3 A and in secondary 0.16 A.

Q. A transformer has $500$ primary turns and $10$ secondary turns. If the secondary has resistive load of $15 Ω$ , the currents in the primary and secondary respectively, are

$0.16 A, 3.2 \times 1 0^{- 3} A$

$3.2 \times 1 0^{- 3} A, 0.16 A$

$0.16 A, 0.16 A$

$3.2 \times 1 0^{- 3} A, 3.2 \times 1 0^{- 3} A$

As $\frac{N _{s}}{N _{p}} = \frac{I _{p}}{I _{s}} \Rightarrow \frac{10}{500} = \frac{I _{p}}{I _{s}}$
or $\frac{I _{p}}{I _{s}} = \frac{1}{50}$ or $I_{s} = 50 I_{p}$
This condition is satisfied only when current in primary is $3.2 \times 1 0^{- 3}$ A and in secondary 0.16 A.

Q. A transformer has 500 primary turns and 10 secondary turns. If the secondary has resistive load of 15Ω, the currents in the primary and secondary respectively, are

0.16A,3.2×10−3A

3.2×10−3A,0.16A

0.16A,0.16A

3.2×10−3A,3.2×10−3A