Q.
A toy car of mass 2.0kg is moving towards negative Y -axis with a velocity of 0.5m/s . It takes a turn towards X -axis with a velocity of 0.4m/s . How much is the change in the linear momentum of the car due to the turn ?
Given, mass of car, m=2kg
Initial velocity, vi=−0.5j^m/s
So, initial momentum pi=2×(−0.5j^) =−1.0j^kgm/s
Now, final velocity, vf=0.4i^m/s
So, final momentum, pf=2×(0.4i^) =0.8i^kgm/s
Now, change in momentum =pf−pi =(0.8i^)−(n−10j^)=0.8i^+j^ =(0.8i^+1.0j^)kgm/s