A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia 2 kg-m2. If wheel starts rotating from rest then, its angular displacement in 10 seconds will be:

Question

A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia 2 kg-m2. If wheel starts rotating from rest then, its angular displacement in 10 seconds will be: (A) 750 rad (B) 1500 rad (C) 3000 rad (D) 6000 rad

Tardigrade Admin · Accepted Answer

τ =I α 30 =2 × α ⇒ α =15 rad / sec 2 From equation of angular motion θ=ω0 t+(1/2) α t2 =0+(1/2) × 15 × 10 × 10 =750 rad

Q. A torque of $30 N - m$ is acting on a wheel of mass $5 k g$ and moment of inertia $2 k g - m 2$ . If wheel starts rotating from rest then, its angular displacement in $10$ seconds will be:

750 rad

1500 rad

3000 rad

6000 rad

$τ = I α$
$30 = 2 \times α$
$\Rightarrow α = 15 r a d / se c^{2}$
From equation of angular motion
$θ = ω_{0} t + \frac{1}{2} α t^{2}$
$= 0 + \frac{1}{2} \times 15 \times 10 \times 10$
$= 750 r a d$

Q. A torque of 30N−m is acting on a wheel of mass 5kg and moment of inertia 2kg−m2. If wheel starts rotating from rest then, its angular displacement in 10 seconds will be: