A thin uniform wire of mass m and length l is bent into a circle. The moment of inertia of the wire about an axis passing through its one end and perpendicular to the plane of the circle is

Question

A thin uniform wire of mass m and length l is bent into a circle. The moment of inertia of the wire about an axis passing through its one end and perpendicular to the plane of the circle is (A) (2 mL2/π2) (B) (mL2/π2) (C) (mL2/2π2) (D) (mL2/3π2)

Tardigrade Admin · Accepted Answer

2 π r=L r=(L/2 π), I=2 m r2=2 m((L/2 π))2

Q. A thin uniform wire of mass $m$ and length $l$ is bent into a circle. The moment of inertia of the wire about an axis passing through its one end and perpendicular to the plane of the circle is

$\frac{2 m L ^{2}}{π ^{2}}$

$\frac{m L ^{2}}{π ^{2}}$

$\frac{m L ^{2}}{2 π ^{2}}$

$\frac{m L ^{2}}{3 π ^{2}}$

$2 π r = L$
$r = \frac{L}{2 π}, I = 2 m r^{2} = 2 m (\frac{L}{2 π})^{2}$

Q. A thin uniform wire of mass m and length l is bent into a circle. The moment of inertia of the wire about an axis passing through its one end and perpendicular to the plane of the circle is

π22mL2​

π2mL2​

2π2mL2​

3π2mL2​