A thin rod of length L is bent to form a semicircle. The mass of the rod is M. What will be the gravitational potential at the centre of the circle?

Question

A thin rod of length L is bent to form a semicircle. The mass of the rod is M. What will be the gravitational potential at the centre of the circle? (A) -(G M/L) (B) -(G M/2 L) (C) -(π G M/L) (D) -(π G M/2 L)

Tardigrade Admin · Accepted Answer

Correct answer is (c) -(π G M/L)

Q. A thin rod of length $L$ is bent to form a semicircle. The mass of the rod is $M$ . What will be the gravitational potential at the centre of the circle?

$- \frac{GM}{L}$

$- \frac{GM}{2 L}$

$- \frac{π GM}{L}$

$- \frac{π GM}{2 L}$

Correct answer is (c) $- \frac{π GM}{L}$

Q. A thin rod of length L is bent to form a semicircle. The mass of the rod is M. What will be the gravitational potential at the centre of the circle?

−LGM​

−2LGM​

−LπGM​

−2LπGM​