A tap supplies water at 15° C and another tap connected to geyser supplies water at 95° C. How much hot water must be taken so as to get 60 kg of water at 35° C ?

Question

A tap supplies water at 15° C and another tap connected to geyser supplies water at 95° C. How much hot water must be taken so as to get 60 kg of water at 35° C ? (A) 5 kg (B) 10 kg (C) 15 kg (D) 20 kg

Tardigrade Admin · Accepted Answer

Let x kg of hot water be taken than cold water taken is (60-x) kg . Using heat gained = heat lost x× 1000× (95-35)=(60-x)× 1000 × (35-15) x× 1000× 60=(60-x)× 1000× 20 3x=60-x 4x=60 x=(60/4)=15 kg

Q. A tap supplies water at $1 5^{\circ} C$ and another tap connected to geyser supplies water at $9 5^{\circ} C$ . How much hot water must be taken so as to get $60 k g$ of water at $3 5^{\circ} C ?$

5 kg

10 kg

15 kg

20 kg

Let $x k g$ of hot water be taken than cold water taken is
$(60 - x) k g$ . Using heat gained = heat lost
$x \times 1000 \times (95 - 35) = (60 - x) \times 1000$
$\times (35 - 15)$
$x \times 1000 \times 60 = (60 - x) \times 1000 \times 20$
$3 x = 60 - x$
$4 x = 60$
$x = \frac{60}{4} = 15 k g$

Q. A tap supplies water at 15∘C and another tap connected to geyser supplies water at 95∘C. How much hot water must be taken so as to get 60kg of water at 35∘C?