A symmetric star shaped conducting wire loop is carrying a steady state current I as shown in the figure. The distance between the diametrically opposite vertices of the star is 4𝑎. The magnitude of the magnetic field at the center of the loop is

Question

A symmetric star shaped conducting wire loop is carrying a steady state current I as shown in the figure. The distance between the diametrically opposite vertices of the star is 4𝑎. The magnitude of the magnetic field at the center of the loop is (A) (μoI/4π a)6[√3-1] (B) (μoI/4π a)6[√3+1] (C) (μoI/4π a)3[√3-1] (D) (μoI/4π a)3[2-√3]

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b91875fdb637d3d0596714cfaeef4120-.png" /> B =12((μ0 I /4 π a ))( sin 60- sin 30)

Q. A symmetric star shaped conducting wire loop is carrying a steady state current $I$ as shown in the figure. The distance between the diametrically opposite vertices of the star is $4 a .$ The magnitude of the magnetic field at the center of the loop is

$\frac{μ _{o} I}{4 πa} 6 [3 - 1]$

$\frac{μ _{o} I}{4 πa} 6 [3 + 1]$

$\frac{μ _{o} I}{4 πa} 3 [3 - 1]$

$\frac{μ _{o} I}{4 πa} 3 [2 - 3]$

$B = 12 (\frac{μ _{0} I}{4 πa}) (sin 60 - sin 30)$

Q. A symmetric star shaped conducting wire loop is carrying a steady state current I as shown in the figure. The distance between the diametrically opposite vertices of the star is 4a. The magnitude of the magnetic field at the center of the loop is

4πaμo​I​6[3​−1]

4πaμo​I​6[3​+1]

4πaμo​I​3[3​−1]

4πaμo​I​3[2−3​]