Question

A suitable unit for gravitational constant is

• A. $kgm{s}^{-1}$
• B. $N{m}^{-1}$
• C. $N{m}^{2}k{g}^{-2}$
• D. $kgmss$

Answer 1

Answer: (C)

$F=\frac{G_{m_1{m}_2}}{d^2}$,
$\therefore G=\frac{F{d}^2}{m_1{m}_2}=N{m}^2/k{g}^2$