Q.
A string of negligible mass passing over a clamped pulley of mass m supports a body of mass M as shown in figure. The force exerted by the clamp on the pulley is.
A free body diagram of a mass pully system is shown below
Now, tension in the string T−Mg=0 ⇒T=Mg
Force in vertical direction, F1=T+mg ⇒F1=Mg+mg=(M+m)g
Similarly, force in horizontal direction F2=T=Mg
Now, the resultant force Fres=F12+F22+2F1F2cos90∘ ⇒Fres=F12+F22=(M+m)2g2+M2g2 ⇒Fres=g(M+m)2+M2
Hence, the resultant force is g(M+m)2+M2