A string 2.0 m long and fixed at its ends is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is :

Question

A string 2.0 m long and fixed at its ends is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is : (A) 320 m/s, 120 Hz (B) 180 m/s, 80 Hz (C) 180 m/s, 120 Hz (D) 320 m/s, 80 Hz

Tardigrade Admin · Accepted Answer

3((v/2ℓ)) =240 3 (v/2×2) = 240 v = 320 m/s fundamental frequency = (v/2ℓ) = (320/2×2) = 80

Q. A string $2.0 m$ long and fixed at its ends is driven by a $240 Hz$ vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is :

320 m/s, 120 Hz

180 m/s, 80 Hz

180 m/s, 120 Hz

320 m/s, 80 Hz

$3 (\frac{v}{2 ℓ}) = 240$
$3 \frac{v}{2 \times 2} = 240$
$v = 320 m / s$
fundamental frequency $= \frac{v}{2 ℓ} = \frac{320}{2 \times 2} = 80$

Q. A string 2.0m long and fixed at its ends is driven by a 240Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is :