A stone is moved in a horizontal circle of radius 4 m by means of a string at a height of 20 m above the ground. The string breaks and the particle flies off horizontally, striking the ground 10 m away. The centripetal acceleration during circular motion is

Question

A stone is moved in a horizontal circle of radius 4 m by means of a string at a height of 20 m above the ground. The string breaks and the particle flies off horizontally, striking the ground 10 m away. The centripetal acceleration during circular motion is (A) 6.25 ms -2 (B) 12.5 ms -2 (C) 18.75 ms -2 (D) 25 ms -2

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5d679eef2cd7d53cb22b0781dc0f5df4-.png" /> y =(g x2/2 v2) 20 =(10(102)/2 v2) ⇒ v2 =25 ac =(v2/R)=(25/4) =6.25 m / s 2

Q. A stone is moved in a horizontal circle of radius $4 m$ by means of a string at a height of $20 m$ above the ground. The string breaks and the particle flies off horizontally, striking the ground $10 m$ away. The centripetal acceleration during circular motion is

$6.25 m s^{- 2}$

$12.5 m s^{- 2}$

$18.75 m s^{- 2}$

$25 m s^{- 2}$

$y = \frac{g x ^{2}}{2 v ^{2}}$
$20 = \frac{10 ( 1 0 ^{2} )}{2 v ^{2}}$
$\Rightarrow v^{2} = 25$
$a_{c} = \frac{v ^{2}}{R} = \frac{25}{4}$
$= 6.25 m / s^{2}$

Q. A stone is moved in a horizontal circle of radius 4m by means of a string at a height of 20m above the ground. The string breaks and the particle flies off horizontally, striking the ground 10m away. The centripetal acceleration during circular motion is

6.25ms−2

12.5ms−2

18.75ms−2

25ms−2