A stick of mass m and length l is pivoted at one end and is displaced through an angle θ. The increase in potential energy is

Question

A stick of mass m and length l is pivoted at one end and is displaced through an angle θ. The increase in potential energy is (A) m g (l/2)(1- cos θ) (B) m g (l/2)(1+ cos θ) (C) m g (l/2)(1- sin θ) (D) m g (l/2)(1+ sin θ)

Tardigrade Admin · Accepted Answer

Using mechanical energy conservation U=(m g l/2)(1- cos θ)

Q. A stick of mass $m$ and length $l$ is pivoted at one end and is displaced through an angle $θ$ . The increase in potential energy is

$m g \frac{l}{2} (1 - cos θ)$

$m g \frac{l}{2} (1 + cos θ)$

$m g \frac{l}{2} (1 - sin θ)$

$m g \frac{l}{2} (1 + sin θ)$

Using mechanical energy conservation
$U = \frac{m g l}{2} (1 - cos θ)$

Q. A stick of mass m and length l is pivoted at one end and is displaced through an angle θ. The increase in potential energy is

mg2l​(1−cosθ)

mg2l​(1+cosθ)

mg2l​(1−sinθ)

mg2l​(1+sinθ)