Q.
A spacecraft of mass 100kg breaks into two when its velocity is 104ms−1 . After the break, a mass of 10kg of the space craft is left stationary. The velocity of the remaining part is
Given, m=100kg,m2=10kg and u=104ms−1
From conservation of momentum, m⋅u=m1v1+m2v2 100×104=20×0+90×v2 100×104=0+90×v2 v2=90100×104 v2=1.1×104 v2=11.11×103ms−1