A sound wave of frequency 'v' Hz initially travels a distance of 1 km in air. Then it gets reflected into a water reservoir of depth 600 m. The frequency of the wave at the bottom of the reservoir is (Vair = 340 m/s ; Vwater = 148 m/s)

Question

A sound wave of frequency 'v' Hz initially travels a distance of 1 km in air. Then it gets reflected into a water reservoir of depth 600 m. The frequency of the wave at the bottom of the reservoir is (Vair = 340 m/s ; Vwater = 148 m/s) (A) > v Hz  (B) < v Hz  (C) v Hz (D) 0 (the sound wave gets attenuated by water completely)

Tardigrade Admin · Accepted Answer

The frequency of sound wave remains constant

Q. A sound wave of frequency $^{'} v^{'}$ Hz initially travels a distance of $1 km$ in air. Then it gets reflected into a water reservoir of depth $600 m$ . The frequency of the wave at the bottom of the reservoir is
$(V_{ai r} = 340 m / s; V_{w a t er} = 148 m / s)$

$> v Hz$

$< v Hz$

v Hz

0 (the sound wave gets attenuated by water completely)

The frequency of sound wave remains constant

Q. A sound wave of frequency ′v′ Hz initially travels a distance of 1km in air. Then it gets reflected into a water reservoir of depth 600m. The frequency of the wave at the bottom of the reservoir is (Vair​=340m/s;Vwater​=148m/s)

>vHz

<vHz

v Hz

0 (the sound wave gets attenuated by water completely)

The frequency of sound wave remains constant

Q. A sound wave of frequency $^{'} v^{'}$ Hz initially travels a distance of $1 km$ in air. Then it gets reflected into a water reservoir of depth $600 m$ . The frequency of the wave at the bottom of the reservoir is
$(V_{ai r} = 340 m / s; V_{w a t er} = 148 m / s)$

$> v Hz$

$< v Hz$