Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The molarity of the solution prepared
Q. A solution is made by dissolving
49
g
of
H
2
S
O
4
in
250
m
L
of water. The molarity of the solution prepared
2647
197
Some Basic Concepts of Chemistry
Report Error
A
2
M
61%
B
1
M
14%
C
4
M
16%
D
5
M
9%
Solution:
Molarity
=
Mol.wt. of solute
Wt. of solute
×
Volume of soln. (mL)
1000
=
98
49
×
1000
250
=
2
M