A small sphere of mass m is suspended by a thread of length l . It is raised up to the height of suspension with thread fully stretched and released. Then the maximum tension in the thread will be

Question

A small sphere of mass m is suspended by a thread of length l . It is raised up to the height of suspension with thread fully stretched and released. Then the maximum tension in the thread will be <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-x9e08d3txzjm.png" /> (A) mg (B) 2mg (C) 3mg (D) 6mg

Tardigrade Admin · Accepted Answer

Applying energy conservation beginarrayl mgl =(1/2) mv 2 v 2=2 gl endarray Step 2: Calculate tension at bottom most point beginarrayl T - mg =( mv 2/1) T - mg =( m 2 gl / l ) T =3 mg endarray

Q. A small sphere of mass $m$ is suspended by a thread of length $l$ . It is raised up to the height of suspension with thread fully stretched and released. Then the maximum tension in the thread will be

$m g$

$2 m g$

$3 m g$

$6 m g$

Applying energy conservation
$m g l = \frac{1}{2} m v^{2} v^{2} = 2 g l$
Step 2: Calculate tension at bottom most point
$T - m g = \frac{m v ^{2}}{1} T - m g = \frac{m 2 g l}{l} T = 3 m g$

Q. A small sphere of mass m is suspended by a thread of length l . It is raised up to the height of suspension with thread fully stretched and released. Then the maximum tension in the thread will be

mg

2mg

3mg

6mg