A small block of mass M moves with velocity 5 m s- 1 towards an another block of same mass M placed at a distance of 2 m on a rough horizontal surface. Coefficient of friction between the block and ground is 0.25 . The collision between the two blocks is elastic, the separation between the blocks, when both of them come to rest, is ( g=10 m s- 2 )

Question

A small block of mass M moves with velocity 5 m s- 1 towards an another block of same mass M placed at a distance of 2 m on a rough horizontal surface. Coefficient of friction between the block and ground is 0.25 . The collision between the two blocks is elastic, the separation between the blocks, when both of them come to rest, is ( g=10 m s- 2 ) (A) 3m (B) 4m (C) 2m (D) 1.5m

Tardigrade Admin · Accepted Answer

Retardation due to friction a=μ g=(0.25)(.10.) =2.5 ms- 2 Collision is elastic, i.e. after collision first block comes to rest and the second block acquires the velocity of the first block. Or we can understand it in this manner that second block is permanently at rest while only the first block moves. Distance travelled by it will be s=(v2/2 a)=((5)2/(2) (. 2.5 .))=5m ∴ The final separation will be ( 5-2 ) =3m

$3 m$

$4 m$

$2 m$

$1.5 m$