A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :

Question

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by : (A) 2π√(L/√g2+((qE)m)2)  (B) 2π√(L/(g+ (qE)m)) (C) 2π √(L/(g- (qE)m)) (D) 2π √(L/√g2 - (q2E2)m2)

Tardigrade Admin · Accepted Answer

geff = √g2 + ((qE/m))2 T = 2π √(ℓ/geff ) = 2π √(ℓ/√g2 +((qE)m)2)

Q. A simple pendulum of length $L$ is placed between the plates of a parallel plate capacitor having electric field $E$ , as shown in figure. Its bob has mass $m$ and charge $q$ . The time period of the pendulum is given by :

$2 π \frac{L}{g ^{2} + ( \frac{qE}{m} ) ^{2}}$

$2 π \frac{L}{( g + \frac{qE}{m} )}$

$2 π \frac{L}{( g - \frac{qE}{m} )}$

$2 π \frac{L}{g ^{2} - \frac{q ^{2} E ^{2}}{m ^{2}}}$

$g_{e ff} = g^{2} + (\frac{qE}{m})^{2}$
$T = 2 π \frac{ℓ}{g _{e ff}}$
$= 2 π \frac{ℓ}{g ^{2} + ( \frac{qE}{m} ) ^{2}}$

Q. A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :

2πg2+(mqE​)2​L​​

2π(g+mqE​)L​​

2π(g−mqE​)L​​

2πg2−m2q2E2​​L​​