A simple pendulum is oscillating with an angular amplitude 60° . If mass of bob is 50 gram, the tension in the string at mean position is ( g =10 ms -2)

Question

A simple pendulum is oscillating with an angular amplitude 60° . If mass of bob is 50 gram, the tension in the string at mean position is ( g =10 ms -2) (A) 0.5 N (B) 1 N (C) 1.5 N (D) 2 N

Tardigrade Admin · Accepted Answer

Tension T=m g+(m v2/r)=m g+(m/l)[2 g l(1- cos θ)] =m g+2 m g(1- cos θ)=m g+(2 m g/2)=2 m g =2(50 × 10-3)(10)=1 N

Q. A simple pendulum is oscillating with an angular amplitude $6 0^{\circ} .$ If mass of bob is $50 g r am,$ the tension in the string at mean position is $(g = 10 m s^{- 2})$

$0.5 N$

$1 N$

$1.5 N$

$2 N$

Tension $T = m g + \frac{m v ^{2}}{r} = m g + \frac{m}{l} [2 g l (1 - cos θ)]$
$= m g + 2 m g (1 - cos θ) = m g + \frac{2 m g}{2} = 2 m g$
$= 2 (50 \times 1 0^{- 3}) (10) = 1 N$

Q. A simple pendulum is oscillating with an angular amplitude 60∘. If mass of bob is 50gram, the tension in the string at mean position is (g=10ms−2)

0.5N

1N

1.5N

2N