A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration 3 ms-2 is

Question

A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration 3 ms-2 is (A) t √(9.8/12.8) (B) t √(12.8/9.8) (C) t √(9.8/6.8) (D) t √(6.8/9.8)

Tardigrade Admin · Accepted Answer

t propto (1/√9.8), t prime propto (1/√12.8) (∴ g prime=9.8+3=12.8) ∴ (t prime/t)=√(9.8/12.8) ⇒ t prime=√(9.8/12.8) t

Q. A simple pendulum has time period ' $t$ '. Its time period in a lift which is moving upwards with acceleration $3 m s^{- 2}$ is

$t \frac{9.8}{12.8}$

$t \frac{12.8}{9.8}$

$t \frac{9.8}{6.8}$

$t \frac{6.8}{9.8}$

$t \propto \frac{1}{9.8}, t^{'} \propto \frac{1}{12.8}$
$(∴ g^{'} = 9.8 + 3 = 12.8)$
$∴ \frac{t ^{'}}{t} = \frac{9.8}{12.8}$
$\Rightarrow t^{'} = \frac{9.8}{12.8} t$

Q. A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration 3ms−2 is

t12.89.8​​

t9.812.8​​

t6.89.8​​

t9.86.8​​