A simple harmonic motion is represented by: y = 5(sin3 π t + √3 cos3 π t) cm The amplitude and time period of the motion are:

Question

A simple harmonic motion is represented by: y = 5(sin3 π t + √3 cos3 π t) cm The amplitude and time period of the motion are: (A) 5cm, (3/2)s (B) 5cm, (2/3)s (C) 10cm, (3/2)s (D) 10cm, (2/3)s

Tardigrade Admin · Accepted Answer

y = 5 [sin(3 π t) + √3 cos(3π t)] =10 sin (3π t + (π/3)) Amplitude = 10 cm T = (2π/w) = (2π/3π) = (2/3)sec

Q. A simple harmonic motion is represented by: $y = 5 (s in 3 π t + 3 cos 3 π t) c m$ The amplitude and time period of the motion are:

$5 c m, \frac{3}{2} s$

$5 c m, \frac{2}{3} s$

$10 c m, \frac{3}{2} s$

$10 c m, \frac{2}{3} s$

$y = 5 [s in (3 π t) + 3 cos (3 π t)]$
$= 10 s in (3 π t + \frac{π}{3})$
Amplitude = 10 cm
$T = \frac{2 π}{w} = \frac{2 π}{3 π} = \frac{2}{3} sec$

Q. A simple harmonic motion is represented by: y=5(sin3πt+3​cos3πt)cm The amplitude and time period of the motion are:

5cm,23​s

5cm,32​s

10cm,23​s

10cm,32​s