A ship of mass 3× 107 kg initially at rest, is pulled by a force of 5× 104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is

Question

A ship of mass 3× 107 kg initially at rest, is pulled by a force of 5× 104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is (A) 1.5 m/s (B) 60 m/s (C) 0.1 m/s (D) 5 m/s

Tardigrade Admin · Accepted Answer

a=(F/m)=(5× 104/3×107)=(5/3)×10-3 m/s2 v=√2as =√2×(5/3)×10-3×3 = 0.1 m/s

Q. A ship of mass $3 \times 1 0^{7} k g$ initially at rest, is pulled by a force of $5 \times 1 0^{4} N$ through a distance of $3 m$ . Assuming that the resistance due to water is negligible, the speed of the ship is

1.5 m/s

60 m/s

0.1 m/s

5 m/s

$a = \frac{F}{m} = \frac{5 \times 1 0 ^{4}}{3 \times 1 0 ^{7}} = \frac{5}{3} \times 1 0^{- 3} m / s^{2}$
$v = 2 a s$
$= 2 \times \frac{5}{3} \times 1 0^{- 3} \times 3$
$= 0.1 m / s$

Q. A ship of mass 3×107kg initially at rest, is pulled by a force of 5×104N through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is