A seconds pendulum is mounted in a rocket. Its period of oscillation will decrease when rocket is

Question

A seconds pendulum is mounted in a rocket. Its period of oscillation will decrease when rocket is (A) moving down with uniform acceleration (B) moving around the earth in geostationary orbit (C) moving up with uniform velocity (D) moving up with uniform acceleration

Tardigrade Admin · Accepted Answer

Period of oscillation T=2 π √(l/g). Therefore T will decrease when acceleration (g) increases. And g will increase when the rocket moves up with a uniform acceleration.

Q. A seconds pendulum is mounted in a rocket. Its period of oscillation will decrease when rocket is

moving down with uniform acceleration

moving around the earth in geostationary orbit

moving up with uniform velocity

moving up with uniform acceleration

Period of oscillation $T = 2 π \frac{l}{g}$ .
Therefore $T$ will decrease when acceleration $(g)$ increases.
And $g$ will increase when the rocket moves up with a uniform acceleration.

Q. A seconds pendulum is mounted in a rocket. Its period of oscillation will decrease when rocket is

moving down with uniform acceleration

moving around the earth in geostationary orbit

moving up with uniform velocity

moving up with uniform acceleration

Period of oscillation T=2πgl​​. Therefore T will decrease when acceleration (g) increases. And g will increase when the rocket moves up with a uniform acceleration.

Period of oscillation $T = 2 π \frac{l}{g}$ .
Therefore $T$ will decrease when acceleration $(g)$ increases.
And $g$ will increase when the rocket moves up with a uniform acceleration.