Question

A rolling object rolls without slipping down an inclined plane (angle of inclination $\theta$ ). If the minimum acceleration it can have is $\frac{g\sin \theta }{n}$. The value of $n$ is ___.

Answer 1

Answer: 2

$a=\frac{g\sin \theta }{1+\frac{I}{M{R}^2}}$
$a$ is minimum, if $I$ is maximum.
$I_{\max }=M{R}^2$ [for ring]
$\Rightarrow a_{\min }=\frac{g\sin \theta }{1+\frac{M{R}^2}{M{R}^2}}=\frac{g\sin \theta }{2}$