A rigid container with thermally insulated walls contains a coil of resistance 100 Ω, carrying current 1 A. Change in internal energy after 5 min will be

Question

A rigid container with thermally insulated walls contains a coil of resistance 100 Ω, carrying current 1 A. Change in internal energy after 5 min will be (A) Zero (B) 10 kJ (C) 20 kJ (D) 30 kJ

Tardigrade Admin · Accepted Answer

W = 0. Therefore, from first law of thermodynamics, Δ U = Δ Q = i2Rt = (I)2 (100) (5 × 60)J = 30kJ

Q. A rigid container with thermally insulated walls contains a coil of resistance 100 $Ω$ , carrying current 1 A. Change in internal energy after 5 min will be

Zero

10 kJ

20 kJ

30 kJ

W = 0. Therefore, from first law of thermodynamics,
$Δ U = Δ Q = i^{2} Rt$
$= (I)^{2} (100) (5 \times 60) J = 30 k J$

Q. A rigid container with thermally insulated walls contains a coil of resistance 100 Ω, carrying current 1 A. Change in internal energy after 5 min will be