A rigid container with thermally insulated walls contains a coil of resistance 100 Ω , carrying current 1 A. Change in internal energy after 5 min will be:

Question

A rigid container with thermally insulated walls contains a coil of resistance 100 Ω , carrying current 1 A. Change in internal energy after 5 min will be: (A) zero (B) 10 kJ (C) 20 kJ (D) 30 kJ

Tardigrade Admin · Accepted Answer

W=0 Therefore, from first law of thermodynamics Δ U=Δ Q=i2 R t =(1)2 × 100(5 × 60) =30 k J

Q. A rigid container with thermally insulated walls contains a coil of resistance $100 Ω,$ carrying current $1 A$ . Change in internal energy after $5 min$ will be:

zero

10 kJ

20 kJ

30 kJ

$W = 0$ Therefore, from first law of thermodynamics
$Δ U = Δ Q = i^{2} Rt$
$= (1)^{2} \times 100 (5 \times 60)$
$= 30 k J$

Q. A rigid container with thermally insulated walls contains a coil of resistance 100Ω, carrying current 1A. Change in internal energy after 5min will be: