A resistance of 300 Ω and an inductance of (1/π) henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is

Question

A resistance of 300 Ω and an inductance of (1/π) henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is (A)  tan -1 (4/3) (B)  tan -1 (3/4) (C)  tan -1 (3/2) (D)  tan -1 (2/5)

Tardigrade Admin · Accepted Answer

Phase angle tan varphi=(ω L/R)=(2 π × 200/300) × (1/π) =(4/3) ∴ varphi= tan -1 (4/3)

Q. A resistance of $300 Ω$ and an inductance of $\frac{1}{π}$ henry are connected in series to a ac voltage of $20$ volts and $200 Hz$ frequency. The phase angle between the voltage and current is

$tan^{- 1} \frac{4}{3}$

$tan^{- 1} \frac{3}{4}$

$tan^{- 1} \frac{3}{2}$

$tan^{- 1} \frac{2}{5}$

Phase angle
$tan φ = \frac{ω L}{R} = \frac{2 π \times 200}{300} \times \frac{1}{π}$
$= \frac{4}{3}$
$∴ φ = tan^{- 1} \frac{4}{3}$

Q. A resistance of 300Ω and an inductance of π1​ henry are connected in series to a ac voltage of 20 volts and 200Hz frequency. The phase angle between the voltage and current is

tan−134​

tan−143​

tan−123​

tan−152​